A phone starts at level percent and uses per_hour percent every hour. Write hours_left(level, per_hour) that returns how many full hours it runs before the level is 0 or below (per_hour > 0).
hours_left(100, 25) → 4
hours_left(50, 15) → 4
Submit runs 4 tests, including hidden edge cases.
Each hint gives a little more help. Try on your own first.
Run your code to see the output here.