Write cheapest(prices) that returns the item with the lowest price in a non-empty dictionary (the first one if tied).
cheapest({'tea': 20, 'coffee': 35, 'juice': 15})
→ 'juice'cheapest({'a': 5})
→ 'a'Submit runs 4 tests, including hidden edge cases.
Each hint gives a little more help. Try on your own first.
Run your code to see the output here.