Write count_value(d, x) that returns how many keys have the value x.
count_value({'Asha': 'Pune', 'Om': 'Delhi', 'Ravi': 'Pune'}, 'Pune')
→ 2count_value({}, 1)
→ 0Submit runs 4 tests, including hidden edge cases.
Each hint gives a little more help. Try on your own first.
Run your code to see the output here.